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发表于 2009-9-1 16:31:15
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#include <stdio.h> 9 Z& u* i! j# F3 q3 `/ Y# }! g' I
#include <string.h> 1 U$ k. C3 g* R% {7 M. _
#include <errno.h>
9 `0 J* e- l. D3 r* U7 H( U#include <unistd.h>
: F- p% z; r$ J* l) {#include <fcntl.h>
* a& `) M& j/ h: j#include <linux/kd.h>
$ }* z2 j9 M/ L3 D' c @$ y#include <linux/keyboard.h>
, x5 t$ s2 _/ N& t#include <termios.h>
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: \3 X$ T1 w* T. i$ j/ N#define KEY_DOWN 0x100
' u$ E; r9 {1 c4 q#define KEY_UP 0x000 v7 }) p+ ^# T& D" f- j
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int oldmode;
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3 G t- O7 N3 O7 istruct termios new;
. K9 N2 y0 H7 H. Vstruct termios old;
. F8 X) s* c; {
( r7 V, B' o3 i) ^& O/ Hint get_key_input(void)
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8 k y" }2 i# S6 B6 J; X rint keyboard;+ U6 {, A! X" K
int keyboardcode;1 j, U' |+ v/ O% Q0 y, `
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keyboard = init_keyboard();8 ~: V! H$ g2 `
do{
. g6 [" h8 }5 L/ t! hkeyboardcode = poll_keyboard(keyboard);
; J1 D) z: A6 v. C; [) r' L. O! Y! dif((keyboardcode != 0) && (keyboardcode & KEY_DOWN)){ , F l n K% k3 P* o& P
keyboardcode = keyboardcode & 0xFF;- y/ w+ J9 V2 V- j
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}
; s% S# L; J6 i- A5 N}while( keyboard != 0x58);
1 R4 V: Q1 l: z7 Y8 Eexit_keyboard(keyboard);: H8 O; d& T. h' \& Q
return 0;
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; H. A5 `8 j* X. ~2 t5 ~int exit_keyboard(int keyboard)5 w; e9 w! ~/ [
{
( X0 Y- C4 M% Kioctl(keyboard, KDSKBMODE, oldmode);
( E8 |1 P- }$ _tcsetattr( keyboard, 0, &old);% w. L: z2 e- r3 ]- g, w3 J9 |
close(keyboard);
# P7 L% j. a) l3 sreturn 0;
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int init_keyboard(void)
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int keyboard;8 _9 V! j# O5 {+ ?. Z1 ^# C
6 ?! p3 V( M, @% M5 Y8 E+ D5 Kkeyboard = open("/dev/tty", O_RDONLY);
" {" D, y8 p& @0 nioctl(keyboard, KDGKBMODE, &oldmode);
0 z. V. G4 H- y z$ c! Qtcgetattr( keyboard, &old);3 W* {6 z5 I9 V; D. M& @
tcgetattr( keyboard, &new);) p7 `5 i9 g: W
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new.c_lflag &= ~(ICANON | ECHO | ISIG);
9 y* F& X6 l1 V- Mnew.c_iflag = 0;
5 }4 a; J0 W+ y( Z Anew.c_cc[VMIN] = 0;
8 }2 z; S8 T# j2 h( L- J9 o: onew.c_cc[VTIME] = 1;
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tcsetattr(keyboard, TCSAFLUSH, &new);
% `4 C. }& t) W% U6 _7 l) eioctl(keyboard, KDSKBMODE, K_RAW);3 w a% J, ~7 w3 ]) v
. m, C: b- V3 r7 T, S# E! t$ rreturn keyboard;
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}
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int poll_keyboard(int keyboard)
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unsigned char buf[5];
9 ^: m* l. z& k! [( ]7 f6 Aint n;
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T+ w* a$ l( e' g1 {7 dint kc = 0;
, z, S3 ?% |1 K% U& d; O! L1 I& h) }int i = 0;- K) k% l% N" P& M3 y9 N
int s = 0;' P4 B) _1 |3 c+ c& R# g4 `
n = read(keyboard, &buf, sizeof(buf)); & R' _7 [& i, j4 r+ V
while( i < n){
' y j; j5 Q( T1 _s = (buf & 0x80) ? 0:1;
8 ~/ ~5 ~# @ ^. w( @$ Fs = s << 8;% C! A/ y5 V1 b0 D+ j
if((i + 2) < n && (buf & 0x7F) == 0 && ( buf[i+1] & 0x80) != 0 && (buf[i+2] & 0x80) != 0){
& @ Q4 p1 h% N* u0 ]% s/ y- |2 }+ gkc = ((buf[i+1] & 0x7F ) << 7 ) |(buf[i+2] & 0x7F);8 B0 h# C9 R: o1 B+ c8 B2 l
i += 3;8 Y! P" X( h6 h' S; f$ e; Z
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else{
6 Q I* o, C2 N- L) q6 jkc = buf & 0x7F;
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}
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kc = s | kc;* E# l* V6 S) ?9 C B' U
return kc;
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